Question

if 9^x+2= 720+9^x find the value of (4x)^1/2 (solve it)

Answer 1

Hello Mate!

${9}^{x + 2} = 720 + {9}^{x} \\ {9}^{x} \times {9}^{2} = 720 + {9}^{x} \\ {9}^{x} \times {9}^{2} - {9}^{x} = 720 \\ {9}^{x} (81 - 1) = 720 \\ {9}^{x} = \frac{720}{80} \\ {9}^{x} = 9 \\ x = 1 \\ \\ {(4x)}^{ \frac{1}{2} } = {4}^{ \frac{1}{2} } = 2$


Hope it helps☺!

Answer 2

Answer:

The value is 2

Step-by-step explanation:

Given the expression

$9^{x+2}= 720+9^x$

$\text{we have to find the value of }(4x)^\frac{1}{2}$

$9^{x+2}= 720+9^x$

$9^x\times 9^2= 720+9^x$

$9^x\times 9^2-9^x=720$

$9^x(9^2-1)=720$

$9^x\times 80=720$

$9^x=\frac{720}{80}=9$

$9^x=9^1$

Comparing both sides we get x=1

$(4x)^\frac{1}{2}=(4(1))^{\frac{1}{2}}=4^{\frac{1}{2}}=2$