Question

If 96500 coulomb of electricity is passed through CuSO4 solution it will liberate

Answer 1

At the cathode:

$Cu_{2}+2e^{-} = Cu$

at anode:

$4OH^{-} = 2H_{2}O +O_{2} +4e^{-}$

Faraday’s constant = 96500 С\$mol$

​ 96500C96500C will liberate =0.25 moles