If 9x*+Kx+1=0 has equal roots,
find the value of k
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Answer:
Step-by-step explanation:
Given equation
9x² +kx + 1 = 0
Comparing the given equation with ax² + bx + c = 0,then a = 9, b = k and c = 1.
Given equation has equal roots,
Discriminant = D = b² - 4ac = 0
⇒k² - 4 ( 9) ( 1) = 0
⇒ k² - 36 = 0
⇒ k² = 36
⇒ k = √36
⇒ k = 6 is the answer.
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