Question

prove that :- log 81/8 - 2log3/2 + 3log2/3 + log3/4 = 0​

Answer 1

Step-by-step explanation:

= log81/8 - 2log3/2 + 3log2/3 + log3/4

= log81 - log8 - 2(log3-log2) +3(log2-log3)+(log3-log4)

= log3^4 - log2³ - 2log3 + 2log2 + 3log2 - 3log3 + log3 - log2²

= (4log3 - 2log3 -3log3+log3)-( 3log2-2log2 - 3log2 + 2log2)

= 0 + 0

= 0