if A(0,5) B(6,11) and C(10,7) are vertices of triangle ABC,D and E are the mid point of AB and AC respectively then find the area of ADE
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Given: A(0,5), B(6,11) and C(10,7), D and E are the mid point of AB and AC
To find: find the area of ADE
Solution:
- To find the area of triangle ADE, we need to find the coordinates of D and E first,
- So coordinates of D are
(x2+x1)/2
= 6+0/2
3 units
and (y2+y1)/2
11+5/2
8 units
D = (3,8)
- coordinates of E are
(x2+x1)/2
= 10+0/2
5 units
and (y2+y1)/2
7+5/2
6 units
E=(5,6)
- So now area of triangle ADE =
1/2 { x1(y2-y3) + x2 (y3-y1) + x3 ( y1-y2) }
1/2 { 0 + 3(6-8) + 5(0-8) }
1/2 { -6 - 40 }
-46/ 2
-23
- As it is area so negative sign can be ignores,
- so,
- area = 23 sq units.
Answer:
Area of triangle ADE = 23 sq units.
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