If a=-0, b= -1, find the value of a3 + b3 + 3a²b + 3ab²?
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Answer:
Step-by-step explanation:
a= 0 and b= -1
so,
a3+b3+3a^2b+3ab^2 = ( a+ b)^3= ( 0 -1 )^3= -1
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