Question

If A=0 then 2sin A = sin2A?​

Answer 1

Step-by-step explanation:

A=0

L.H.S.– 2sinA = 2×sin0 = 2×0 = 0

R.H.S.– sin2A = sin2×0 = sin0 = 0

So, L.H.S. = R.H.S. [proved]

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Answer 2

Sin 2A=2sinA cos A

We know that A=0

So we'll get 2sin0 cos0

Sin 2A=0

We know that,

2 sinA cos A =0

2sinA=0-cosA

2sinA=0-cos0

2sinA=0-0

2sinA=0

Therefore sin2A=2sinA

Proved.

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