Question

IF A{1,1/4,1/9,1/16,1/25} THEN EXPRESS A IN SET BUILDER FORM

Answer 1

let the set is A
now, A = {1/x^{2}: x is a natural number} 

Answer 2

Answer:

The set builder form of A is $A=\{\frac{1}{x^2}:x\leq 5,x\in N\}$.

Step-by-step explanation:

The given set is

$A=\{1,\frac{1}{4},\frac{1}{9},\frac{1}{16},\frac{1}{25}\}$

$1=\frac{1}{1^2}$

$\frac{1}{4}=\frac{1}{2^2}$

$\frac{1}{9}=\frac{1}{3^2}$

$\frac{1}{16}=\frac{1}{4^2}$

$\frac{1}{25}=\frac{1}{5^2}$

Therefore the number is in the form of $\frac{1}{x^2}$, where x is a natural number less than equal to 5.

$A=\{\frac{1}{x^2}:x\leq 5,x\in N\}$

Therefore set builder form of A is $A=\{\frac{1}{x^2}:x\leq 5,x\in N\}$.