Question

If A = {1, 2, 3, 4, 5}, write the relation a R b such that a + b = 8, a ,b € A. Write the domain, range & co-domain.

Answer 1

$\textbf{Given:}$

$\mathsf{A=\{1,2,3,4,5\}}$

$\mathsf{aRb\iff\,a+b=8}$

$\textbf{To find:}$

$\textsf{Doamin, Range and codomain}$

$\textbf{Solution:}$

$\mathsf{aRb\iff\,a+b=8}$

$\mathsf{3+5=8\implies\;_3R_5}$

$\mathsf{4+4=8\implies\;_4R_4}$

$\mathsf{5+3=8\implies\;_5R_3}$

$\therefore\mathsf{R=\{(3,5),(4,4),(5,3)\}}$

$\mathsf{Domain=\{3,4,5\}}$

$\mathsf{Range=\{3,4,5\}}$

$\mathsf{Co-domain=\{1,2,3,4,5\}}$

$\textbf{Find more:}$

If R = {x, y)/x = 2y} is a relation defined on A = {1, 2, 3, 4, 6, 7, 8} then write all elements of R Also

https://brainly.in/question/19887787

Find the domain and range of the relation,

R = ( (x, y) : x,y e Z, xy = 4}

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Answer 2

$\textbf\red{Given:}$

$\mathsf{A=\{1,2,3,4,5\}}$

$\mathsf{aRb\iff\,a+b=8}$

$\textbf\red{To find:}$

$\textsf{Doamin, Range and codomain}$

$\textbf\pink{Solution:}$

$\mathsf{aRb\iff\,a+b=8}$

$\mathsf{3+5=8\implies\;_3R_5}$

$\mathsf{4+4=8\implies\;_4R_4}$

$\mathsf{5+3=8\implies\;_5R_3}$

$\therefore\mathsf{R=\{(3,5),(4,4),(5,3)\}}$

$\mathsf{Domain=\{3,4,5\}}$

$\mathsf{Range=\{3,4,5\}}$

$\mathsf{Co-domain=\{1,2,3,4,5\}}$