Question

if A=(1,2,3,4)and B=(3,4,5,6) find n(AUB)x(A intersection B)x(A∆B)​

Answer 1

Answer:

n(AUB)x(A intersection B)x(A∆B)

Answer 2

Question: If A = (1,2,3,4) and B = (3,4,5,6) find n(AUB) × n(A∩B) × n(A∩B).​

Answer:

The value of n(AUB) × n(A∩B) × n(A∩B) is 24.

Step-by-step explanation:

Consider the given sets as follows:

$A=(1,2,3,4)$

$B=(3,4,5,6)$

Step 1 of 3

Computing number of elements in $A$ union $B$.

A∪B = {$1, 2, 3, 4, 5, 6$}

So, the number of elements in A∪B = 6

i.e., n(A∪B) = 6

Step 2 of 3

Computing number of elements in $A$ intersection $B$.

A∩B = {3, 4}

So, the number of elements in A∩B = 2

i.e., n(A∩B) = 2

Step 3 of 3

Find the value of n(AUB) × n(A∩B) × n(A∩B).

From step 1 and 2, we have

n(A∪B) = 6 and n(A∩B) = 2

Then,

n(AUB) × n(A∩B) × n(A∩B) = 6 × 2 × 2

                                           = 24

Therefore, the final answer is 24.

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