Question

if a ={1,2,3,4} and b={3,4,5} then n [ (a-b)u(b-a)] is equal to

Answer 1

a={1,2,3,4}        b={3,4,5}

n[(a-b)u(b-a)]=?

Now,

we have to first find the value of a-b and b-a

a-b={1,2}........1

b-a={5}...........2

now,

n[(a-b)u(b-a)]=?

now,

substitute equation 1 and 2 in n[(a-b)u(b-a)].

implies

n[(a-b)u(b-a)]= n[{1,2}u{5}]

n[(a-b)u(b-a)]= n{1,2,5}

therefore, n[(a-b)u(b-a)]= n{1,2,5}

this is your answer for the above question.

If you like it please do mark me as a brainliest

All the best!!!!!