If A={1,2,3} B={a,b,c} then verify the result n{AuB}=n(A)+n(B)-n(AintersectionB)
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I don't know what is it sorry dudd
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A={1,2,3}
B={a,b,c}
N(AuB)=n(A)+n(B)-n(AintersectionB)
LHS=>n(AuB)
=(1,2,3,a,b,c)
=>n=6
RHS=>n(A)=3
=>n(B)=3
=>n(AintersectionB)=0
Therefore,LHS=RHS
=>6=6
Hence,proved
B={a,b,c}
N(AuB)=n(A)+n(B)-n(AintersectionB)
LHS=>n(AuB)
=(1,2,3,a,b,c)
=>n=6
RHS=>n(A)=3
=>n(B)=3
=>n(AintersectionB)=0
Therefore,LHS=RHS
=>6=6
Hence,proved
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