Question

If A ( 1 , 2 ) ; B ( -1, 2 ) ; C ( x , 4 ) and D ( 2,5 ) are vertices of parallelogram then write the value of x.​

Answer 1

Answer:

Step-by-step explanation:

In parallelogram ABCD

AB=CD

$AB^2=CD^2\\\\(1+1)^2+(2-2)^2=(x-2)^2+(4-5)^2\\\\(x-2)^2+1-4=0\\\\(x-2)^2-(\sqrt{3} )^2\\\\(x-2-\sqrt{3)} (x-2+\sqrt{3} )=0\\\\\bf Thus \ x= 2+\sqrt{3} \ Or \ 2-\sqrt{3}$