Question

If a(1,-2) , b(-2,3 ,c(2,-5) are the vertices of triangle abc then the equation of median be is'

Answer 1

Answer:

13x+7y+5=0

Step-by-step explanation:

Please see the attachment for solution

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Answer 2

The equation of median BE is 13x+7y+5=0.

Step-by-step explanation:

The vertices of triangle are A(1,-2) , B(-2,3) ,C(2,-5).

We need to find the equation of median BE.

Median from a vertex divides the opposite side in two equal prats.

BE is median it means E is the midpoint of AC.

$E=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})=(\dfrac{1+2}{2},\dfrac{-2-5}{2})=(1.5,-3.5)$

Median BE passes through the points B(-2,3) and E(1.5,-3.5). The equation of BE is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-3=\dfrac{-3.5-3}{1.5+2}(x+2)$

$y-3=-\dfrac{13}{7}(x+2)$

Multiply both sides by 7.

$7(y-3)=-13(x+2)$

$7y-21=-13x-26$

$13x+7y+26-21=0$

$13x+7y+5=0$

Therefore, the equation of median BE is 13x+7y+5=0.

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