If A(1,2),B(4,3) and C(6,6) are the three vertices of a parallelogram ABCD, find the coordinates of fourth vertex D.
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Answered by
8
Place the points in a graph paper with respect to OX and OY rectangular axes and you will see that the vertex D has coordinates (3,5).
Hope this helps you.
Hope this helps you.
Swarup1998:
It's ok. I thought simply to put the points on graph paper and found the solution.
Answered by
23
AC = BD
They will have the same midpt. (Since, in a parallelogram diagonals bisect each other)
Now, To find the midpt we will use midpoint formula for AC.
Let the point E(x,y).
E(x,y) = [x₂+x₁/2 , y₂+y₁/2]
= 6+1/2 , 6+2/2
= [7/2 , 4]
The midpoint of AC and BD is [7/2 , 4]
Now,
E(7/2,4) = [x₂+x₁/2 , y₂+y₁/2]
= [x+4/2 , y+3/2]
For x,
x+4/2 = 7/2
x + 4 = 7
x = 3
For y,
y+3/2 = 4
y+3 = 8
y = 5
Hence the coordinates of the fourth vertex is [3,5].
They will have the same midpt. (Since, in a parallelogram diagonals bisect each other)
Now, To find the midpt we will use midpoint formula for AC.
Let the point E(x,y).
E(x,y) = [x₂+x₁/2 , y₂+y₁/2]
= 6+1/2 , 6+2/2
= [7/2 , 4]
The midpoint of AC and BD is [7/2 , 4]
Now,
E(7/2,4) = [x₂+x₁/2 , y₂+y₁/2]
= [x+4/2 , y+3/2]
For x,
x+4/2 = 7/2
x + 4 = 7
x = 3
For y,
y+3/2 = 4
y+3 = 8
y = 5
Hence the coordinates of the fourth vertex is [3,5].
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