If a = 1+√2009/2
,then (a^3 – 503a + 500)^10 =
1) 3^10
2) 2^10
3) 5^10
4) 4^10
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(a³ - 503a - 500)¹⁰ = 2¹⁰ ; a = (1 + √2009)/2
Step-by-step explanation:
Given, a = (1 + √2009)/2
∴ (a³ - 503a - 500)¹⁰
= [{(1 + √2009)/2}³ - 503 (1 + √2009)/2 - 500]¹⁰
= [(1 + √2009)/2 * {(1 + √2009)/2}² - 503 (1 + √2009)/2 - 500]¹⁰
= [(1 + √2009)/2 * {(1 + 2√2009 + 2009)/4 - 503} - 500]¹⁰
= [(1 + √2009)/2 * {(2010 + 2√2009 - 2012)/4} - 500]¹⁰
= [(1 + √2009)/2 * (- 2 + 2√2009)/4 - 500]¹⁰
= [(√2009 + 1)/2 * (√2009 - 1)/2 - 500]¹⁰
= [(2009 - 1)/4 - 500]¹⁰
= [2008/4 - 500]¹⁰
= [502 - 500]¹⁰
= 2¹⁰
Therefore option (b) = 2¹⁰ is correct.
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