If A = (1 3)
(3 4)
find the value of x and y such that A^2 − + = 0,
Where I is the identity matrix
Answers
Answered by
27
Answer:
A=[
43
25
]
A
2
−xA+yI=0
[
43
25
] [
43
25
] −x [
43
25
] +y [
10
01
]=0
[
2227
1831
] − [
4x3x
2x5x
] +y [
10
01
]=0
[
22−4x+y27−3x+0
18−2x+031−5x+y
]=[
00
00
]
22−4x+y=0
4x−y=22------(1)
18−2x=0
x=9
put in (1) 4×9−y=22
36−22=y
y=14
∴x+y=23
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