Question

if A ={1,3,5} and B={2,3} then
(i) find AXB and BXA
(ii) Is AXB =BXA? if not why?
(iii) show that n(AXB)=n(BXA)=n(A)xn(B)


solution plz....
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Answer 1

HERE'S UR ANSWER...

PLS CHECK IT ONCE....

Answer 2

Answer:

The correct option is B A × B = {(1,2), (1,3), (3,2), (3,3), (5,2), (5,3)}

B × A = {(2,1), (2,3), (2,5), (3,1), (3,3), (3,5)}

Given that A = {1,3,5} and B = {2,3}

A × B = {1,3,5} × {2,3}

= {(1,2), (1,3), (3,2), (3,3), (5,2), (5,3)}

B × A = {2,3} × {1,3,5}

= {(2,1), (2,3), (2,5), (3,1), (3,3), (3,5)}