If a = 1 – √7/1 + √7 and b=1 + √7/1 - √7,then find the value of a^2+ab+b^2/a^2-ab+b^2
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since a = 1-√7/1+√7 on conjucating we get
a= 1-√7 / 1+√7 x 1+√7 / 1+√7
a= (1+√7)^2 / (1+√7)(1-√7)
a= 1 + 7 -2√7 / 1-7 = 6 - 2√7/6
a= 2 (3-√7) / 6 = 3 - √7 /3
doing the same on b we get b = 3 - √7 / 3
now substituting a and be on a^2 + ab + b^2 / a^2 - ab + b^2 we get
= 41/23
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