If [a + (1/a)²– 2[a – (1/a)] = 12, then which of the following is a value of ‘a’?
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Step-by-step explanation:
a + 1/a² -2a + 2/a = 12
a³ +1 -2a³ + 2a = 12a²
a³ +12a² -2a -1= 0
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