Question

if a =1 and b =2 ,find the value of (a/b+b/a)^b

Answer 1

Answer:

Given (a/b) = (b/c)

= > b^2 = ac -------- (1)

Therefore, a,b,c are in GP.

Now,

LHS = (1/b - c) + (1/b - a)

= (b - a) + (b - c)/(b - c)(b - a)

= b - a + b - c/(b^2 - ab - bc + ca)

= 2b - (a + c)/b^2 - b(a + c) + ca

= 2b - (a + c)/b^2 - b(a + c) + b^2 (from (1))

= 2b - (a + c)/2b^2 - b(a + c)

= 2b - (a + c)/ b(2b - (a + c)

= 1/b.

Hope this helps!

☺

Answer 2

Hey mate

Here is your answer