Question

if a=1,b=-2,c=-3 find the value of (a³+b³+c³-3abc)
____________
ab+bc+ca-(a²+b²+c²)

plz answer me i will thanks u make you brainlist
and rate u 5 star
​

Answer 1

Step-by-step explanation:

Given: a2+b2+c2−ab−bc−ca=0

⟹12.[2a2+2b2+2c2−2ab−2bc−2ca]=0

⟹12.[(a2−2ab+b2)+(b2−2bc+c2)+(c2−2ac+a2)]=0

⟹12.[(a−b)2+(b−c)2+(c−a)2]=0

Since the above statement is a sum of square terms, for all real values of a,b,c , the above statement is true only when a=b=c

⟹a3+b3+c3=3a3

3abc=3a3