Question

If a=−1, b=−23 and c=−34 , then the value of a+b+c is​

Answer 1

Answer:

-58 because + multiplied by - is - itself

Answer 2

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It is given that a:(b+c)=1:3 and c:(a+b)=5:7 and we solve these expressions as follows:

b+ca=31⇒3a=b+c⇒3a−b=c....(1)

a+bc=75⇒7c=5(a+b)⇒7c=5a+5b....(2)

Multiplying the first equation by 7 we get:

7(3a−b)=7c⇒7c=21a−7b....(3)

Now, subtracting equation 2 from equation 3, we have:

7c−7c=(21a−7b)−(5a+5b)⇒0=21a−7b−5a−5b⇒16a=12b⇒b=1216a⇒b=34a

Substituting the value of b in equation 1:

3a−34a=c⇒c=39a−34a⇒c=39a−4a⇒c=35a 

Now, lets find the value of b:(a+c) as shown below:

a+cb=a+35a34a=33a+35a34a=38a34a=34a×8a3=8a4a=21=1:2

hence, b:(a+c)=1:2.