if a=1 is root of equation a4-62a2 +b=0 find value of b
Answers
Answered by
0
Answer:
b=61
Step-by-step explanation:
put the value a=1 in eq.
a4-62a3 +b=0
(1)4-62*(1)2+b=0
1-62+b=0
-61+b=0
b=61.
Similar questions