Question

if a + 1 upon a is equal to 1 find a cube + 1 upon a cube​

Answer 1

Step-by-step explanation:

$a + \frac{1}{a} = 1 \\ lets \: cube \: this \\ \\ ( {a + \frac{1}{a} )}^{3} = {a}^{3} + \frac{1}{ {a}^{3} } + 3(a + \frac{1}{a} ) \\ \\ put \: values$

$( {1})^{3} = {a}^{3} + \frac{1}{ {a}^{3} } + 3(1) \\ 1 - 3 = {a}^{3} + \frac{1}{ {a}^{3} } \\ = - 2$

hence -2 is your answer.......