Math, asked by simrah2770, 11 months ago

if a 10 digit number 2094x843y2 divisible by 88 then the value of (5x-7y) for the largest value of x

Answers

Answered by amitnrw
6

Answer:

-43

Step-by-step explanation:

a 10 digit number 2094x843y2 divisible by 88 then the value of (5x-7y) for the largest value of x

2094x843y2 divisible by 88

88 = 8 * 11

=> divisible by 8 & 11

Divisibility rule for 8

Last 3digit number divisible by 8

=> 3y2  is divisible by 8

=> 312  & 392 are divisible by 8

=> y = 1 or  9

Divisibility rule for 11

2-0+9-4+x-8+4-3+y-2  should be divisible by 11

=> 15 + x + y - 17 should be divisible by 11

=> x + y - 2 should be divisible by 11

Either x + y = 2  or x + y = 13

if y = 1 then x = 1

if y = 9 then x = 4

Largest Value of x = 4

5x-7y for largest value of x

5*4 - 7*9

= -43

Answered by kabirkumar40
7

Answer:

Step-by-step explanation:

Taking y = 5 the value of x comes 8.

Therefore required ans is 5..

Not that -43

Attachments:
Similar questions