Question

If a 10 kg block is dropped from rest, determine the distance it will have covered after 2 seconds

Answer 1

$20 \: m$

Explanation:

$Given, \: \: \: m = 10 \: kg , \: \: g = 10 \: m {s}^{ - 2} \\ and \: \: \: t = 2s, \: \:u = 0 \: m {s}^{ - 1} \\ Let, \: the \: \: distance=s \\ we \: \: know \: \: \boxed{s = ut + \frac{1}{2}g {t}^{2} } \\ Now, \: \: putting \: \: values \\ \: \: \: \: \: \: \: s = 0 \times 2 + \frac{1}{2} \times 10 \times {2}^{2} \\ = 0 + \frac{1}{2} \times 10 \times 4 \\ = \boxed{20 \: m}$