If a =12, b =11 and a+= a++ – --a + --b; What will be the values of a and b?
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Answer:
a=9 b=22
Explanation:
step 1: a = 6 (given)
step 2: b = (++a) + (a++) + (a++) ————(1)
just break this statement into three parts,,,and take first of them..
1) ++a = 7 (pre-increment) so (6+1=7) will be assigned to a.
2) a++ = 7 (post increment) it will remain same here,then value of a will be 8 in next step.
3) a++ = 8 (post increment) so now value of a will be 9 for further.
step 3: Now put the values of these three sub-steps in eq. (1) to get the value of b.
b = 7+7+8 = 22.
step 4 .in sub-step (3) we can say value of a = 9.
so,a = 9, b = 22.
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