Question

If a 12 V battery is connected to the arrangement of resistances given below, calculate (i) the total effective resistance of the arrangement and (ii) the total current flowing in the circuit current through 10 ohm resistor

Answer 1

Answer:

I= 12/10=6/5        ,       I= 12/10=6/5

Explanation:

i) total resistance in 1st series = 10 +20=30 ohm.

total resistance in 2nd series= 5 +25=30 ohm.

total resistance in parallel =1/30+1/30=2/30=1/15.

I= 12/10=6/5

ii) potential difference ( v) =12v

R=10 ohm

we know that, v=IR

so, 12= I×10

I= 12/10=6/5

Answer 2

Hey Here is Answer:

In Series

Req = R₁ +R₂

Req = 10 + 20

Req = 30 ohm

In Series

Req = R₁ + R₂

Req = 5 + 25

Req = 30 ohm

In parallel

1/Req = 1/R₁ +1/R₂

1/Req = 1/30 + 1/30

1/Req = 2/30

Req = 30/2 ⇒ 15 ohm

Current passing through 10 ohm Resistor

I = V/R

I = 12 / 10

I = 1.2 A