If A(-14,6), B(2,-2), C(2,5) are the vertices of a triangle ABC, find the length of the median through A.
Pls help me
Anonymous:
find the midpoint of BC then apply distance formula between A and that point !
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Answer:
16.62 cm
Step-by-step explanation:
Let the mid-point be D.
Coordinates of D are:
D = [2 + 2/2, -2 + 5/2]
= [4/2, 3/2]
= [2,1.5]
Distance from A to D:
= √(x₁ - x₂)² + (y₁ - y₂)²
= √(-14 - 2)² + (6 - 1.5)²
= √256 + 20.25
= √276.25
= 16.62 cm.
Hope it helps!
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