Question

If A={2,3,5,7,11} B={2,4,6,8} and C={1,3,5,7,9} then find A-(BuC)​

Answer 1

Answer:

Given,

\begin{gathered}\begin{array}{l}A = \left\{ {2,3,5,7,11} \right\}\\B = \left\{ {2,4,6,8} \right\}\\C = \left\{ {1,3,5,7,9} \right\}\end{array}\end{gathered}

A={2,3,5,7,11}

B={2,4,6,8}

C={1,3,5,7,9}

A - \left( {B \cap C} \right) = ?A−(B∩C)=?

Solution,

\begin{gathered}\begin{array}{l}B \cap C = \left\{ {2,4,6,8} \right\} \cap \left\{ {1,3,5,7,9} \right\}\\ \Rightarrow B \cap C = \phi \end{array}\end{gathered}

B∩C={2,4,6,8}∩{1,3,5,7,9}

⇒B∩C=ϕ

Further solution,

\begin{gathered}\begin{array}{l} = A - \left( {B \cap C} \right)\\ = \left\{ {2,3,5,7,11} \right\} - \phi \\ = \left\{ {2,3,5,7,11} \right\}\end{array}\end{gathered}

=A−(B∩C)

={2,3,5,7,11}−ϕ

={2,3,5,7,11}

Hence, the value ofA - \left( {B \cap C} \right)A−(B∩C) is\left\{ {2,3,5,7,11} \right\}{2,3,5,7,11} .

Answer 2

Answer:

{11}. Please mark me as brainliest.

Step-by-step explanation:

A={2,3,5,7,11} B={2,4,6,8} and C={1,3,5,7,9}

{2,3,5,7,11}-({2,4,6,8}∪{1,3,5,7,9})​

= {2,3,5,7,11}-({1,2,3,4,5,6,7,8,9)}

= {11}