If A=(2,3) B=(-2,3) such that |PA-PB|=4 then find the locus of P
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Given,
A=(4,0)≡(x1,y1),B=(−4,0)≡(x2,y2)
⇒∣PA−PB∣=4
Distance Formula =(x−x1)2+(y−y1)2
⇒(x−4)2+(y−0)2−(x+4)2+(y−0)2=4
⇒(x−4)2+y2=16+(x+4)2+y
⇒4x2+4+8x=x2+16+8x+y2
⇒3x2−y2=12
⇒4x2−12
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