Question

The center of gravity of a hollow cone of height h is at distance 'x' from irs vertex where the value of 'x' is

Answer 1

Answer:

It will be  $\dfrac {2h}{3}$

Explanation:

When the height is $h$

The centre of gravity of hollow cone from base is  $\dfrac{h}{3}$

 and vertex (or top ) is  $h- \dfrac{h}{3} = \dfrac {2h}{3}$