Question

If a=2+√3 prove that m^2-4m+1=0​

Answer 1

Answer:

=$=m^2-4m+1=0\\=(2+\sqrt{3})^{2}-4*2+\sqrt{3}+1 =0\\=2^{2}+3+ 2*2*\sqrt{3}-8 -4\sqrt{3}+1=0\\=8+ 4\sqrt{3} -8- 4\sqrt{3}=0\\ =0=0$

Step-by-step explanation: hence RHS=LHS PROVED

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