Question

If a - 2, 3a and a + 2 are in arithmetic progression, then a =

Answer 1

$\large \red {Hiya \:\:\: Mate}$

a - 2, 3 * a, a + 2

If they are in an A.P,

then, Common Difference (d) is the same.

=> Second Term (A_2) - First term (A_1) = Third Term (A_3) - Second Term (A_2)

=> 3 * a - (a - 2) = a + 2 - (3 * a)

=> (3 * a - a) + 2 = 2 + (a - 3 * a)

=> 2 * a + 2 = 2 - 2 * a

=> 4 * a = 0

=> a = 0

$\large \purple {Hope \:\:\: this \:\:\: helps}$

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