Question

IF A(-2,4) B(0,0) AND C(4,2) ARE THE VERTICES OF A TRIANGLE ABC THEN FIND THE LENGTH OF THE MEDIAN THROUGH THE VERTEX A PLEASE GIVE ME THE CORRECT ANSWER NOT A SIMILAR QUERY AS I AM IN URGENT NEED

Answer 1

Answer:

The length of the median is 5 units.

Step-by-step explanation:

It is given that A(-2,4) B(0,0) and C(4,2). The median is drawn through the vertex A.

The median divides the opposite side it two equal parts.

The midpoint of B and C is

$Midpoint=(\frac{0+4}{2},\frac{2+0}{2})=(2,1)$

The vertex of midpoint (point D) is (2,1)

The distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AD=\sqrt{(-2-2)^2+(4-1)^2}=\sqrt{16+9}=5$

Therefore the length of the median is 5 units.

Answer 2

Here's your answer guys