Question

If a^2 + 4b^2 + 9c^2 -4a -4b -12c +9 =0, then the value of a/2+4b+6c is?​

Answer 1

Answer:

a^2 + 4b^2 + 9c^2 -4a -4b -12c +9 =0

=> (a-2)^2 + (2b-1)^2 + (3c-2)^2 = 0

=> a=2 , 2b=1 , 3c=2.

So, a/2 +4b+6c = 1+2+4 = 7.

✔️Hope it will help you.✔️

Answer 2

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