Question

The ionization potential for the electron in the
ground state of hydrogen atom is 13.6 eV. What
would be the ionization potential for the electron in
the first excited state of Li2+?
(1) 54.4 eV
(2) 5.4 eV
(3) 30.6 eV
(4) 84.4 eV​

Answer 1

Answer:

IE = 13.6ev

delta e =13.6z^2(1/n1^2 - 1/n2^2)

delta E = 30.6 eV

( as value of z=3, n1= 2 and n2= infinity)

hope it helps