Question

if a^2+a=1, prove that a^6+4a^3-1=0​

Answer 1

Step-by-step explanation:

a² + a = 1

cubing on both sides

(a² + a)³ = (1)³

(a²)³ + a³ + 3(a²)(a)(a² + a) = 1

a^6 + a³ + 3a³(1) = 1

a^6 + 4a³ = 1

a^6 + 4a³ - 1 = 0.

Hence proved.

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