Question

. if a=2 and b=1, then what is the value of log (a+b)(a^2-b^2)? 1) 1 2) -1 3) 2 4) -2

Answer 1

a=2
B=1
(a+b)(a^2-b^2)
a^2+2ab+b^2. ( it's the formula)
2^2+2*2*1+1^2
4+2+1
(7)

a^2-b^2
(a+b)(a-b)
(2+1)(2-1)
3*1
(3). (is the answer)

hope this helps you

Answer 2

Given,

a = 2

b = 1

To Find,

log(a + b)(a^2-b^2) =?

Solution,

Equation ⇒ $log(a + b) (a^2 - b^2)$

Equation ⇒$log(2 + 1) (2^2 - 1^2)$

Equation ⇒$log(3) (4 - 1)$

Equation ⇒$log(3) (3)$

Equation ⇒$log(9)$

Equation ⇒$log(9) = 0.95$

Equation ⇒log(9) = 1 (Approx)

Hence, the value of log (a+b)(a^2-b^2) is 1. Option(1) is correct answer.