Question

if a=2 and b=3 then find the value of (a^b+b^a)^-1

Answer 1

Heya ☺

Given that

a = 2 ; b = 3

(a^b + b^a)^ -1

= (2^3 + 3^2)^ - 1

= (8 + 9)^-1

= (17)^ -1

= 1/17






Thanks

Answer 2

Given,

• a=2 and b=3

To find,

• We have to find the value of $(a^b +b^a)^{-1}$.

Solution,

We can simply find the value of $(a^b +b^a)^{-1}$ by using the given conditions a = 2 and b = 3.

Substitute a = 2 and b = 3 in $(a^b +b^a)^{-1}$, we get

                    = (2³ +3²)⁻¹

                    = (8 +9)⁻¹

                    = (17)⁻¹

Using law of exponent,

                   $a^{-m} = 1/a^m$, we get

                  = 1/17

Hence, if a = 2 and b = 3, then the value of $(a^b +b^a)^{-1}$ 1/17.