Question

if a^2+b^2=100,ab=48,find the value of a+b

Answer 1

Hey,

(a+b)² = a² + b² +2ab

(a+b)² = 100 + 2(48)

(a+b)² = 100 + 96

(a+b)² = 196

(a+b) = √196

(a+b) = 14

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Answer 2

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$a^2 + b^2 =100. ;ab=48 ;a+b$

$(a+b)^2=.a^2 + b^2 +2ab$

$(a+b)^2=.100+2*48$

$(a+b)^2=.100+96$

$(a+b)^2=.196$

$(a+b)=.root 196$

$\huge{a+b = 14}$