Math, asked by deepanshiaroras1371, 9 months ago

If a^2+b^2=13 and ab=6,find
3(a+b)^2-2(a-b)^2

Answers

Answered by manimodala73
6

Step-by-step explanation:

(a+b)^2=a^2+b^2+2ab

=13+2(6)

=25

(a+b)^2=25

(a+b) =5

(a-b)^2=a^2+b^2-2ab

=13-2(6)

=1

a-b = 1

3(a+b)^2-2(a-b)^2

=3*25-2*1

=75-2

=73

Similar questions