Question

If a^2+b^2=37 and ab=1 find value of following
1 (a+b)
2 (a-b) ​

Answer 1

Answer:

${a}^{2} + {b}^{2} = 37 \\ \\ ab = 1 \\ \\ \\ {a}^{2} + {b}^{2} = 37 \\ \\ (a + b)^{2} - 2ab = 37 \\ \\ ({a + b})^{2} - 2 \times 1 = 37 \\ \\ ({a + b})^{2} = 37 + 2 \\ \\ ( {a + b})^{2} = 39 \\ \\ (a + b) = + - \sqrt{ 39}$

$( {a - b})^{2} + 2ab = 37 \\ \\ (a - b)^{2} + 2 \times 1 = 37 \\ \\ \\ ({a - b})^{2} = 35 \\ \\ (a - b) = + - \sqrt{35}$

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