Question

if a^2 + b^2 = 41 , ab = 20 find the value of a-b(a-b)^2

Answer 1

Step-by-step explanation:

using the formula (a+b)²

if a^2 + b^2 = 41 , ab = 20

(a-b)²= a²+b²-2ab

(a-b)²= 41-2×20

a-b = √1

a-b= 1

find the value of a-b(a-b)^2

substitute :

1(1)²

= 1

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Answer 2

Answer:

Given that

a^2+b^2=41

ab=20

Step-by-step explanation:

(a-b)^2=a^2+b^2-2ab=41-2(20)

(a-b)^2=41-40=1

a-b=1

(a-b)(a-b)^2=(1)(1)=1