Question

If a^2+b^2=41 and ab=4, find the values of:-
(I) a+b
(II) a-b​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

a-b)=√33a+b=√49=7

Step-by-step explanation:

(a+b)^2= a^2+b^2 + 2ab

= 41+ 8=49

a+b=√49=7

(a-b)^2= a^2+b^2 - 2ab

= 41-8=33

(a-b)=√33