If a^2+b^2=41 and ab=4, find the values of:-
(I) a+b
(II) a-b
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Answer:
a-b)=√33a+b=√49=7
Step-by-step explanation:
(a+b)^2= a^2+b^2 + 2ab
= 41+ 8=49
a+b=√49=7
(a-b)^2= a^2+b^2 - 2ab
= 41-8=33
(a-b)=√33
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