If a^2+b^2=73 and ab =24,find the value of a-b
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Step-by-step explanation:
(a-b)²= a²+b²-2ab
(a-b)²= 73-2×24
(a-b)²= 73-48
(a-b)²= 25
a-b= 5
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Answered by
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Answer:
(a-b)^2=a^2+b^2-2ab
=73-2(24)
=73-48
=25
a-b=√25
a-b=5
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