Math, asked by anshashamsi3, 1 month ago

If a^2+b^2=73 and ab =24,find the value of a-b

Answers

Answered by amanraj56
0

Step-by-step explanation:

(a-b)²= a²+b²-2ab

(a-b)²= 73-2×24

(a-b)²= 73-48

(a-b)²= 25

a-b= 5

#666

Answered by sainlab1895
0

Answer:

(a-b)^2=a^2+b^2-2ab

=73-2(24)

=73-48

=25

a-b=√25

a-b=5

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