Question

if a^2+b^2=99 and ab= 9, find the value of (a+b)​

Answer 1

Answer:

a^2+b^2=99

ab=9

[a+b]^2-ab=a^2+b^2

[a+b]^2-ab=99

[a+b]^2-9=99

[a+b]^2=108

a+b=$6\sqrt{3}$