If a^2+b^2+c^2=16 and ab+bc+ac=10, find a+b+c
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(a+b+c)² = (a²+b²+c²+2ab+2bc+2ac)
=[(a²+b²+c²)+2(ab+bc+ac)]
∵a²+b²+c² =16 and (ab+bc+ac= 10
so, (a+b+c)² = 16 +2×10
=16+20 = 36
⇒(a+b+c) = √36 = 6
=[(a²+b²+c²)+2(ab+bc+ac)]
∵a²+b²+c² =16 and (ab+bc+ac= 10
so, (a+b+c)² = 16 +2×10
=16+20 = 36
⇒(a+b+c) = √36 = 6
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