Math, asked by manatMUNNS2ha0r, 1 year ago

If a^2+b^2+c^2=16 and ab+bc+ac=10, find a+b+c

Answers

Answered by qais

(a+b+c)² = (a²+b²+c²+2ab+2bc+2ac)
=[(a²+b²+c²)+2(ab+bc+ac)]

∵a²+b²+c² =16 and (ab+bc+ac= 10

so, (a+b+c)² = 16 +2×10
=16+20 = 36
⇒(a+b+c) = √36 = 6

qais: we are asking question to know the process and not the answer only...and if you have any problem then ask the moderator.

Rahul1998: What moderator

Rahul1998: That kismus?

Kimmus: Do you have problems here @Rahul1998 ??

Kimmus: Dude!! this is not your answer to comment out here.. You've no idea abt what you're talking... You better stop blabbering.. Thank you @RAHUL1998 :)

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