If a^2+b^2+c^2=200and ab+bc+can=28 then find the value of a+b+c
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The value of a+b+c =16
karthiksangwan4:
Pls give the solution
Urgent
Your answer is incorrect and the answer is 256
no it should be route over 256
which is 16
(a+b+c) ^2 = a^2+b^2+c^2+2(ab+bc+ca) =>( a+b+c) ^2=200+2(28) => (a+b+c)
cont. ^2 = 256 => a+b+c = square route of 256 => a+b+c = 16
sorry there were some typing mistakes as my keyboard is not working properly
and > means =>
implies sign
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